document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31870>Question 31870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i had to solve the equation for y. the equation was (sqrt of 2y) +3=11, my answer was 4 ? please help.i hope i typed the equation right the 2y are under the radical sign. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18463 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18463\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (sqrt of 2y) +3=11\r<BR>\n" );
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document.write( "first subtract both sides by 3 and we get ..\r<BR>\n" );
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document.write( "(sqrt of 2y) = 8 \r<BR>\n" );
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document.write( "taking square of both sides we get \r<BR>\n" );
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document.write( "2y = 64 \r<BR>\n" );
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document.write( "divide both sides by 2 and we get..\r<BR>\n" );
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document.write( "y = 32<BR>\n" );
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document.write( "Now if you want to  verify you answer ,,,you can put the values of y in the given equation and if you get LHS = RHS,,,this means that you answer is correct..\r<BR>\n" );
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document.write( "hope this will help you \r<BR>\n" );
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document.write( "Please feel free to revert back for any further queries. </SPAN>\n" );
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