document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=250739>Question 250739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x=-10+y<BR>\n" );
document.write( "-16x-2y=-2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184628 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184628\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here are the two original equations:<BR>\n" );
document.write( "(i) x = -10 + 1y<BR>\n" );
document.write( "(ii) -16x - 2y = -2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Use substitution to solve them. Put (i) into (ii) to get<BR>\n" );
document.write( "-16(-10 + y) - 2y = -2<BR>\n" );
document.write( "160 -16y - 2y = -2<BR>\n" );
document.write( "-18y = -162<BR>\n" );
document.write( "y = 9<BR>\n" );
document.write( "X = -1. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );