document.write( "Question 252604: There are 35 tickets to be sold for the dance. The number of tickets sold to seniors must be four times the number of tickets sold to juniors.
\n" ); document.write( " please give me 2 linear equations and a solution. \r
\n" ); document.write( "\n" ); document.write( "A diamond today costs 10$ more than twice what it cost last year. The sum of the cost (last year and this year) is 2500$. What is the cost of last years diamond?
\n" ); document.write( " i need 2 linear equations and a solution for this question also.\r
\n" ); document.write( "\n" ); document.write( " THANK U SO MUCH!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #184609 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let s = # of senior tickets and j = # of junior tickets\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since there are 35 tickets in total, and we're assuming that only junior and senior tickets are sold, this means that \"j%2Bs=35\". In other words, adding up the two totals will give you the grand total of 35.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, because \"The number of tickets sold to seniors must be four times the number of tickets sold to juniors\", we know that \"s=4j\". In English, the number of senior tickets 's' is 4 times the number of junior tickets 'j'.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"j%2Bs=35\" Start with the first equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"j%2B4j=35\" Plug in \"s=4j\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5j=35\" Combine like terms on the left side.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"j=%2835%29%2F%285%29\" Divide both sides by \"5\" to isolate \"j\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"j=7\" Reduce.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So there are 7 junior tickets.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"s=4j\" Go back to the second equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"s=4%2A7\" Plug in \"j=7\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"s=28\" Multiply\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So there are 28 senior tickets.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "As a check, take note that 28 is indeed 4 times 7 AND 28+7=35. So we've met our conditions.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "======================================================================\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "# 2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let t = cost of diamond today and y = cost of diamond last year\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since \"A diamond today costs 10$ more than twice what it cost last year\", we can say that \"t=2y%2B10\" (ie double the cost from last year 'y' and add 10 to get the new cost today 't').\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, because \"The sum of the cost (last year and this year) is 2500$\", we know that \"t%2By=2500\" (just add up the two individual costs to get the grand total of $2500)\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t%2By=2500\" Start with the second equation.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2y%2B10%2By=2500\" Plug in \"t=2y%2B10\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3y%2B10=2500\" Combine like terms on the left side.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3y=2500-10\" Subtract \"10\" from both sides.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3y=2490\" Combine like terms on the right side.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=%282490%29%2F%283%29\" Divide both sides by \"3\" to isolate \"y\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y=830\" Reduce.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the cost of the diamond last year was $830.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you want to keep going then...\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t=2y%2B10\" Go back to the first equation\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t=2%28830%29%2B10\" Plug in \"y=830\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t=1660%2B10\" Multiply\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t=1670\" Add\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So the cost of the diamond today is $1670.
\n" ); document.write( "
\n" );