document.write( "Question 252604: There are 35 tickets to be sold for the dance. The number of tickets sold to seniors must be four times the number of tickets sold to juniors.
\n" ); document.write( " please give me 2 linear equations and a solution. \r
\n" ); document.write( "\n" ); document.write( "A diamond today costs 10$ more than twice what it cost last year. The sum of the cost (last year and this year) is 2500$. What is the cost of last years diamond?
\n" ); document.write( " i need 2 linear equations and a solution for this question also.\r
\n" ); document.write( "\n" ); document.write( " THANK U SO MUCH!\r
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Algebra.Com's Answer #184608 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
Let's go 1 question at a time. Here is the first one: There are 35 tickets to be sold for the dance. The number of tickets sold to seniors must be four times the number of tickets sold to juniors.
\n" ); document.write( "please give me 2 linear equations and a solution.
\n" ); document.write( "Let S = senior, and J = junior.
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\n" ); document.write( "(i): \"S+%2B+J+=+35\"
\n" ); document.write( "(ii) \"S+=+4J\"
\n" ); document.write( "---
\n" ); document.write( "by substitution, we get
\n" ); document.write( "(iii) 4J + J = 35 - -> J = 7, S = 28.
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\n" ); document.write( "Here is the second question: A diamond today costs 10$ more than twice what it cost last year. The sum of the cost (last year and this year) is 2500$. What is the cost of last years diamond?
\n" ); document.write( "i need 2 linear equations and a solution for this question also.
\n" ); document.write( "Let T = today and Y = last year
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\n" ); document.write( "(i) T = 2Y + 10
\n" ); document.write( "(ii) T + Y = 2500
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\n" ); document.write( "Use substitution to solve.
\n" ); document.write( "(2Y + 10) + Y = 2500
\n" ); document.write( "3Y = 2490
\n" ); document.write( "Y = $830
\n" ); document.write( "T = $1670.
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