document.write( "Question 252596: A rectangle is three times as long as it is wide. The perimeter is 40 feet. Find the width. \n" ); document.write( "

Algebra.Com's Answer #184604 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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A rectangle is three times as long as it is wide.
\n" ); document.write( " The perimeter is 40 feet.
\n" ); document.write( " Find the width.
\n" ); document.write( ":
\n" ); document.write( "Let x = the width
\n" ); document.write( "then
\n" ); document.write( "3x = the length
\n" ); document.write( ":
\n" ); document.write( "The perimeter
\n" ); document.write( "2L = 2W = 40
\n" ); document.write( "so we have:
\n" ); document.write( "2(3x) + 2x = 40
\n" ); document.write( "6x + 2x = 40
\n" ); document.write( "8x = 40
\n" ); document.write( "x = $\"40%2F8\"$
\n" ); document.write( "x = 5 ft is the width
\n" ); document.write( ";
\n" ); document.write( ";
\n" ); document.write( "Check:
\n" ); document.write( "2(15) + 2(5) = 40 \n" ); document.write( "

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