document.write( "Question 252600: Solve for x:
\n" ); document.write( "2x over 3 +4 = x-5
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Algebra.Com's Answer #184600 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"2x%2F3%2B4=x-5\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%282x%2Fcross%283%29%2B4%29=3%28x-5%29\" Multiply both sides by the LCD \"3\" to clear any fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"2x%2B12=3x-15\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=3x-15-12\" Subtract \"12\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-3x=-15-12\" Subtract \"3x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-x=-15-12\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-x=-27\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-27%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=27\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=27\"
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