document.write( "Question 252581: A backpacker hiking into the wilderness area walked 9 miles at a constant rate and then reduced this rate by 1 mph. Another 4 miles was hiked at this reduced rate. The time required to hike the 4 miles was 1 hour less than the time required to walk the 9 miles. Find the rate at which the hiker walked the first 9 miles. \n" ); document.write( "
Algebra.Com's Answer #184589 by JimboP1977(311)\"\" \"About 
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\"9%2Fx+=+t++\" (1)\r
\n" ); document.write( "\n" ); document.write( "\"4%2F%28x-1%29+=+t-1+\"\r
\n" ); document.write( "\n" ); document.write( "Take 1 away from both sides of equation (1).\r
\n" ); document.write( "\n" ); document.write( "\"9%2Fx+-+1+=+4%2F%28x-1%29\"
\n" ); document.write( "\"-1+=+4%2F%28x-1%29+-+9%2Fx\"
\n" ); document.write( "\"-1+=+%28-5x%2B9%29%2F%28x%5E2-x%29\"
\n" ); document.write( "\"-x%5E2%2Bx+=+-5x%2B9\"
\n" ); document.write( "\"-x%5E2%2B6x-9=0\"
\n" ); document.write( "\"x%5E2-6x%2B9=0\"
\n" ); document.write( "\"%28x-3%29%5E2=0\"\r
\n" ); document.write( "\n" ); document.write( "so x = 3\r
\n" ); document.write( "\n" ); document.write( "The rate is 3mph.\r
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