document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252586>Question 252586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> an angles measure is 43 degrees less than 6 times the measure of its complement. find the measure of both angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184578 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184578\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=6y-43 <BR>\n" );
document.write( "x+y=90<BR>\n" );
document.write( "(6y-43)+y=90<BR>\n" );
document.write( "6y-43+y=90<BR>\n" );
document.write( "7y=90+43<BR>\n" );
document.write( "7y=133<BR>\n" );
document.write( "y=133/7<BR>\n" );
document.write( "y=19 ans for the smaller angle.<BR>\n" );
document.write( "x=6*19-43<BR>\n" );
document.write( "x=114-43<BR>\n" );
document.write( "x=71 ans.<BR>\n" );
document.write( "Proof<BR>\n" );
document.write( "19+71=90<BR>\n" );
document.write( "90=90   </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );