document.write( "Question 252580: 3x+y-z=-1
\n" ); document.write( "2y-z=5
\n" ); document.write( "z=1
\n" ); document.write( "

Algebra.Com's Answer #184562 by drk(1908)\"\" \"About 
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(i) 3x+y-z=-1
\n" ); document.write( "(ii) 2y-z=5
\n" ); document.write( "(iii) z=1
\n" ); document.write( "This is quite straight forward. Z = 1. Put z into (ii) to get
\n" ); document.write( "2y-1=5 - -> Y = 3.
\n" ); document.write( "Put y and z into (i) to get
\n" ); document.write( "3x+3-1 = -1 - - > 3x = -3 - -> x = -1.
\n" ); document.write( "So, {-1,3,1}
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