document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252528>Question 252528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the sum of all of the real values of x satisfying the following equation\r<BR>\n" );
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document.write( "(x^2 - 5x + 5)^x^2 - 17x + 70 = 1\r<BR>\n" );
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document.write( "a  5  b  10  c  17  d  22  e  27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184553 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184553\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the roots of this quadratic looking equation is -b/a. So, we get <BR>\n" );
document.write( "17 / (X^2 - 5X + 5). The denominator cannot = 0. So we factor the denominator as<BR>\n" );
document.write( "X = (5 +- sqrt(5))/2<BR>\n" );
document.write( "There are 2 roots here and if we add them, we get 5.<BR>\n" );
document.write( "So, it appears that the answer will be 5 [A].\r<BR>\n" );
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document.write( "Hope that helps.<BR>\n" );
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