document.write( "Question 251079: A family has five children. Assume that the probability of having a boy is 0.5. write the term in the expansion of (b+g)^5 for each outcome described. then evaluate each probability.\r
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Algebra.Com's Answer #184552 by Edwin McCravy(20055)\"\" \"About 
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document.write( "\"b=g=0.5\", \r\n" );
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document.write( "\"%28b%2Bg%29%5E5=b%5E5%2B5b%5E4g%2B10b%5E3g%5E2%2B10b%5E2g%5E3%2B5bg%5E4%2Bg%5E5\"\r\n" );
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document.write( "The 1st term \"b%5E5+=+%280.5%29%5E5+=+0.03125\" is the probability of 5 boys\r\n" );
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document.write( "The 2nd term \"5b%5E4g+=+5%280.5%29%5E4%280.5%29+=+0.15625\" is the probability \r\n" );
document.write( "of 4 boys and 1 girl.\r\n" );
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document.write( "The 3rd term \"10b%5E3g%5E2+=+10%280.5%29%5E3%280.5%29%5E2+=+0.3125\" is the probability \r\n" );
document.write( "of 3 boys and 2 girls. \r\n" );
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document.write( "The 4th term \"10b%5E2g%5E3+=+10%280.5%29%5E2%280.5%29%5E3+=+0.3125\" is the probability \r\n" );
document.write( "of 2 boys and 3 girls.\r\n" );
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document.write( "The 5th term \"5b%5E4g+=+5%280.5%29%280.5%29%5E4+=+0.15625\" is the probability \r\n" );
document.write( "of 1 boy and 4 girls.\r\n" );
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document.write( "The 6th term \"g%5E5+=+%280.5%29%5E5+=+0.03125\" is the probability of 5 girls.\r\n" );
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\n" ); document.write( "a. exactly 3 boys
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document.write( "That's the 3rd term \"10b%5E3g%5E2+=+10%280.5%29%5E3%280.5%29%5E2+=+0.3125\"\r\n" );
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document.write( "That's the 2nd term \"5b%5E4g+=+5%280.5%29%5E4%280.5%29+=+0.15625\" \r\n" );
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document.write( "That's the  5th term \"5bg%5E4+=+5%280.5%29%280.5%29%5E4+=+0.15625\"\r\n" );
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document.write( "Edwin
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