document.write( "Question 252530: when the polynomial 5x^3 + Mx + N is divided by x^2 + x + 1 the remainder is 0.
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\n" ); document.write( "\n" ); document.write( "a -3 b 5 c -5 d 15 e none of the above\r
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Algebra.Com's Answer #184551 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "                                 5x -     5\r\n" );
document.write( "           --------------------------------  \r\n" );
document.write( "x² + x + 1 ) 5x³ + 0x² +         Mx +     N\r\n" );
document.write( "             5x³ + 5x² +         5x\r\n" );
document.write( "             ----------------------\r\n" );
document.write( "                  -5x² +     (M-5)x +     N\r\n" );
document.write( "                  -5x² -         5x -     5\r\n" );
document.write( "                  -------------------------\r\n" );
document.write( "                         [(M-5)+5]x + (N+5)\r\n" );
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document.write( "Remainder = [(M-5)+5]x + (N+5) = 0\r\n" );
document.write( "              [M-5+5]x + (N+5) = 0\r\n" );
document.write( "                    Mx +  N+5  = 0\r\n" );
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document.write( "The only this can be identically 0 for all values of x\r\n" );
document.write( "is for the coefficient of x to be 0.\r\n" );
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document.write( "                      So M=0, so\r\n" );
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document.write( "                         N+5 = 0\r\n" );
document.write( "                           N = -5\r\n" );
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document.write( "Therefore M + N = 0 + (-5) = -5  choice c\r\n" );
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document.write( "Edwin
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