document.write( "Question 252530: when the polynomial 5x^3 + Mx + N is divided by x^2 + x + 1 the remainder is 0.
\n" ); document.write( "what is M + N ?\r
\n" ); document.write( "\n" ); document.write( "a -3 b 5 c -5 d 15 e none of the above\r
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Algebra.Com's Answer #184547 by drk(1908) $\"\"$ $\"About$

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Be careful setting this up. The best way to go here is polynomial division:
\n" ); document.write( " $\"5X%5E3+%2B+0x%5E2+%2B+Mx+%2B+N\"$ / $\"X%5E2+%2B+X+%2B+1\"$
\n" ); document.write( "Dividing carefully gets a quotient of 5X - 5 with a left over part of Mx + N + 5, but the remainder = 0, so,
\n" ); document.write( " $\"Mx+%2B+N+%2B+5+=+0\"$ .
\n" ); document.write( "Now set Mx = 0 and solve for M, M = 0
\n" ); document.write( "Set (N + 5) = 0 and N = -5.\r
\n" ); document.write( "\n" ); document.write( "M + N = 0 + -5 = -5, [C]
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