document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252549>Question 252549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a and b are roots of 7x^2 &#8722; 2002x +182 = 0 , find the value of 1/a + 1/b </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184525 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184525\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a and b are roots of 7x^2 &#8722; 2002x +182 = 0 , find the value of 1/a + 1/b<BR>\n" );
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document.write( "7x^2 &#8722; 2002x +182 = 0<BR>\n" );
document.write( "x^2 - 286x + 26 = 0<BR>\n" );
document.write( "The roots are:<BR>\n" );
document.write( "(-b + sqrt(b^2 - 4ac))/2a and<BR>\n" );
document.write( "(-b - sqrt(b^2 - 4ac))/2a<BR>\n" );
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document.write( "The inverses give:<BR>\n" );
document.write( "2a/(-b + sqrt(b^2 - 4ac)) and<BR>\n" );
document.write( "2a/(-b - sqrt(b^2 - 4ac))<BR>\n" );
document.write( "The sum is:<BR>\n" );
document.write( "2a*2*(-b)/(b^2 - (b^2 - 4ac)<BR>\n" );
document.write( "= 4ab/(4ac) <BR>\n" );
document.write( "= b/c The general solution<BR>\n" );
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document.write( "For this eqn it's -11<BR>\n" );
document.write( "= -11<BR>\n" );
document.write( " </SPAN>\n" );
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