document.write( "Question 252544: Actually I wanted to favtorize:
\n" ); document.write( "\"15x%5E2-22x%2B8\"
\n" ); document.write( "So I multiplied 8 with 15 and got 120.
\n" ); document.write( "The factors came as \"-10\" and \"-12\"
\n" ); document.write( "Then I split the \"22x\" into these 2 numbers, so I got:
\n" ); document.write( "\"15x%5E2-10x-12x%2B8\"
\n" ); document.write( "Then what do I do next? Please help I have no clue!
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Algebra.Com's Answer #184516 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
\"15x%5E2-22x%2B8\"
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\n" ); document.write( "It's a trial and error thing. The 1st term, 15, can be:
\n" ); document.write( "1*15 or 3*5
\n" ); document.write( "The last term, 8, can be 1*8 or 2*4. It's +8, so the signs are the same.
\n" ); document.write( "Start with 1 and 15, ignore the sign but try to get 22 for the middle term:
\n" ); document.write( "(x - 1)*(15x - 8) --> 23x NG
\n" ); document.write( "(3x - 1)*(5x - 8) --> 29x NG
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\n" ); document.write( "(x - 2)*(15x - 4) --> 34x NG
\n" ); document.write( "(3x - 2)*(5x - 4) --> 22x That's it. The 22x is negative, so it's factored.
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\n" ); document.write( "The best approach is to use the quadratic equation, but students are usually subjected to factoring before learning the quadratic equation.
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