document.write( "Question 252544: Actually I wanted to favtorize:
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document.write( "So I multiplied 8 with 15 and got 120.
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document.write( "The factors came as and
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document.write( "Then I split the into these 2 numbers, so I got:
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document.write( "Then what do I do next? Please help I have no clue! \n" );
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Algebra.Com's Answer #184516 by Alan3354(69443) You can put this solution on YOUR website! \n" ); document.write( "----------------- \n" ); document.write( "It's a trial and error thing. The 1st term, 15, can be: \n" ); document.write( "1*15 or 3*5 \n" ); document.write( "The last term, 8, can be 1*8 or 2*4. It's +8, so the signs are the same. \n" ); document.write( "Start with 1 and 15, ignore the sign but try to get 22 for the middle term: \n" ); document.write( "(x - 1)*(15x - 8) --> 23x NG \n" ); document.write( "(3x - 1)*(5x - 8) --> 29x NG \n" ); document.write( "------------------------------ \n" ); document.write( "(x - 2)*(15x - 4) --> 34x NG \n" ); document.write( "(3x - 2)*(5x - 4) --> 22x That's it. The 22x is negative, so it's factored. \n" ); document.write( "------------------------------------ \n" ); document.write( "The best approach is to use the quadratic equation, but students are usually subjected to factoring before learning the quadratic equation. \n" ); document.write( " \n" ); document.write( " |