document.write( "Question 252519: Can someone please point me in the right direction with this experiment. Probabilities and Binomial Experiments.\r
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document.write( "U.S. Population by Region. The U.S. population by region (in millions) for selected years is given in the table. Find the probability that a U.S. resident selected at random satisfies the following:
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document.write( "a.) lived in the West in 1997.
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document.write( "b.) lived in the Midwest in 1995.
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document.write( "c.) lived in the Northwest or Midwest in 1997.
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document.write( "d.) lived in the South or West in 1997.
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document.write( "e.) What are the odds that a randomly selected U.S. resident in 2000 was not from the South?\r
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document.write( "REGION 1995 1997 2000
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document.write( "Northwest 51.4 51.6 53.6
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document.write( "Midwest 61.8 62.5 64.4
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document.write( "South 91.8 94.2 100.2
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document.write( "West 57.7 59.4 63.2\r
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document.write( "(Answers) a. .222 b. .235 c. .426 d. .574 e. 302 to 167
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Algebra.Com's Answer #184491 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! the first thing to do is finish the table with totals for us population for each year in question \n" ); document.write( "REGION 1995 1997 2000 \n" ); document.write( "Northwest 51.4 51.6 53.6 \n" ); document.write( "Midwest 61.8 62.5 64.4 \n" ); document.write( "South 91.8 94.2 100.2 \n" ); document.write( "West 57.7 59.4 63.2 \n" ); document.write( "sum(1995)=51.4+61.8+91.8+57.7 \n" ); document.write( "sum(1997)=51.6+62.5+94.2+59.4=267.7 \n" ); document.write( "sum(2000)=53.6+64.4+100.2+63.2 \n" ); document.write( "a) lived in west in 1997 \n" ); document.write( "59.4/267.7=.2219=.222 \n" ); document.write( "so the part over the whole= probability \n" ); document.write( " |