document.write( "Question 252493: a paint company wants to make a 40% solution from a 25% solution and 50% solution of a chemical. how many gallons of the 25% and 50% mixture do they need to make 100 gallons of the 40% mixture? \n" ); document.write( "
Algebra.Com's Answer #184459 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! a paint company wants to make a 40% solution from a 25% solution and 50% solution of a chemical. \n" ); document.write( " how many gallons of the 25% and 50% mixture do they need to make 100 gallons of the 40% mixture? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 50% solution \n" ); document.write( "then \n" ); document.write( "(100-x) = amt of 25% solution \n" ); document.write( ": \n" ); document.write( ".50x + .25(100-x) = .40(100) \n" ); document.write( ".50x + 25 - .25x = 40 \n" ); document.write( ".50x - .25x = 40 - 25 \n" ); document.write( ".25x = 15 \n" ); document.write( "x = \n" ); document.write( "x = 60 gal of 50% solution \n" ); document.write( "and \n" ); document.write( "100 - 60 = 40 gal of 25% solution \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check \n" ); document.write( ".5(60) + .25(40) = .4(100) \n" ); document.write( "30 + 10 = 40 \n" ); document.write( " |