document.write( "Question 252492: Two cyclist start biking from a trail's start 3 hours apart, The second cyclist travels @ 10mph and starts 3 hourss after the first cyclist who is traveling @ 6mph. How much time will pass before the second cyclist catches up with the first from the time the second cyclist srtarted biking? \n" ); document.write( "
Algebra.Com's Answer #184458 by stanbon(75887)\"\" \"About 
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The second cyclist travels @ 10mph and starts 3 hourss after the first cyclist who is traveling @ 6mph. How much time will pass before the second cyclist catches up with the first from the time the second cyclist srtarted biking?
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\n" ); document.write( "2nd Cyclist DATA:
\n" ); document.write( "rate = 10 mph ; time = x-3 hrs ; distance = rt = 10(x-3) miles
\n" ); document.write( "------
\n" ); document.write( "1st Cyclist DATA:
\n" ); document.write( "rate = 6 mph ; time = x hrs ; distance = rt = 6x miles
\n" ); document.write( "------
\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "10x-30 = 6x
\n" ); document.write( "4x = 30
\n" ); document.write( "x = 7.5 hrs (1st cyclist time)
\n" ); document.write( "---
\n" ); document.write( "x-3 = 4.5 hrs (2nd cyclist time)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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