document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252476>Question 252476</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half-life of a certain radioactive material is 85 days. An initial amount of the material has a mass of 801 kg. Write an exponential function that models the decay of this material. Find how much radioactive material remains after 10 days. Round your answer to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184405 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The half-life of a certain radioactive material is 85 days. This means whatever time we are given, divide it by 85, or t/85.<BR>\n" );
document.write( "An initial amount of the material has a mass of 801 kg. This means that P = 801.<BR>\n" );
document.write( "We can write the half life exponential formula:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+P+%281%2F2%29%5E%28t%2F85%29 ALIGN=MIDDLE  ALT=\"A+=+P+%281%2F2%29%5E%28t%2F85%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Next, t = 10 days. So,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+801%2A%281%2F2%29%5E%2810%2F85%29 ALIGN=MIDDLE  ALT=\"A+=+801%2A%281%2F2%29%5E%2810%2F85%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "A ~ 738.273 Kg. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );