document.write( "Question 252467: First I just hope I'm in the right section, I have been trying to figure out how to solve this problem but I just can't come up with the right formula.\r
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document.write( "An office has an old copying machine and a new one. Working together it takes both machines 6 hours to make all the copies of the annual financial report. Working alone the old machine takes 15 hours longer than the new machine. How long would it take the new machine to make all the copies working alone? \n" );
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Algebra.Com's Answer #184389 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Let n=time it takes for new machine to do the job. \n" ); document.write( "Old does 1/(n+15) the job in 1 hr \n" ); document.write( "together: 1/n + 1/(n+15)=1/6 (in one hour) \n" ); document.write( "6(n+15)+6n=n(n+15) multiply each side by 6n(n+15) (LCM) to eliminate fractions. \n" ); document.write( "6n+90+6n=n^2+15n \n" ); document.write( "12n+90=n^2+15n \n" ); document.write( "n^2+3n-90=0 subtract the left side from the right. \n" ); document.write( "n=8.1 hrs. quadratic formula (below) \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( ". \n" ); document.write( "
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