document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252440>Question 252440</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1+3+5+7+9+11+13+15+17+19=100 now pick any 5 digits which make the sum of 50 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184358 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It's not possible.  The sum of an odd number of odd numbers is always odd.<BR>\n" );
document.write( "There are combinations of 4 or 6 of the numbers that total 50, but not 5 of them.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );