document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252438>Question 252438</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the distance traveled from 2400ft at a descent rate of 15ft/sec with a 5mph wind </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184351 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> what is the distance traveled from 2400ft at a descent rate of 15ft/sec with a 5mph wind?<BR>\n" );
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document.write( "If you mean how far horizontally while descending at that rate:<BR>\n" );
document.write( "2400/15 = 160 seconds<BR>\n" );
document.write( "5 mph = 26400 feet/hour = 440 feet/min = (22/3) feet/sec<BR>\n" );
document.write( "160 sec * 22/3 ft/sec = 3520/3 feet lateral displacement<BR>\n" );
document.write( "=~ 1173 feet </SPAN>\n" );
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