document.write( "Question 252441: one of the roots of the equation 5x^2 + kx = 4 is x = -2 the other root is
\n" ); document.write( "x = ...what ?\r
\n" ); document.write( "\n" ); document.write( "a -5/2 b -2/5 c 2/5 d 2 e 5/2
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Algebra.Com's Answer #184345 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
plug -2 in for x and solve for k
\n" ); document.write( "then solve the equation
\n" ); document.write( "5(-2)^2+k(-2)=4
\n" ); document.write( "5*4-2k=4
\n" ); document.write( "subtract 4 from each side
\n" ); document.write( "4*4-2k=0
\n" ); document.write( "add 2k to each side
\n" ); document.write( "16=2k
\n" ); document.write( "8=k
\n" ); document.write( "5x^2+8x=4
\n" ); document.write( "5x^2+8x-4=0
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"5x%5E2%2B8x%2B-4+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%288%29%5E2-4%2A5%2A-4=144\".
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\n" ); document.write( " Discriminant d=144 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-8%2B-sqrt%28+144+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%288%29%2Bsqrt%28+144+%29%29%2F2%5C5+=+0.4\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%288%29-sqrt%28+144+%29%29%2F2%5C5+=+-2\"
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\n" ); document.write( " Quadratic expression \"5x%5E2%2B8x%2B-4\" can be factored:
\n" ); document.write( " \"5x%5E2%2B8x%2B-4+=+5%28x-0.4%29%2A%28x--2%29\"
\n" ); document.write( " Again, the answer is: 0.4, -2.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+5%2Ax%5E2%2B8%2Ax%2B-4+%29\"

\n" ); document.write( "\n" ); document.write( ".4=2/5
\n" ); document.write( "you could also have divided x+2 into the equation
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