document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252443>Question 252443</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i call my favorite polynomial p(x). when p(x) is divided by x-2 , the quotient is <BR>\n" );
document.write( "3x^2 - x - 5 and the remainder is -1 determine p(-1)\r<BR>\n" );
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document.write( "a -22   b  -4   c -1   d  0    e  2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184344 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> when p(x) is divided by x-2 , the quotient is <BR>\n" );
document.write( "3x^2 - x - 5 and the remainder is -1 determine p(-1)<BR>\n" );
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document.write( "p(x) = (x-2)(3x^2-x-5)-1<BR>\n" );
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document.write( "p(-1) = (-3)(3+1-5)-1<BR>\n" );
document.write( "p(-1) = -3(-1)-1<BR>\n" );
document.write( "p(-1) = 2<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( "a -22 b -4 c -1 d 0 e 2<BR>\n" );
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