document.write( "Question 252428: Can someone please help. I cannot figure out the correct formula. \r
\n" ); document.write( "\n" ); document.write( "Using a Nonlinear System.\r
\n" ); document.write( "\n" ); document.write( "Modeling Circuit Gain. In electronics, cicuit gain is modeled by G = Bt/R + rt, where “R” is the value of a resister, “t” is temperature, Rt is the value of R at temperature “t”, and B is a constant. The sensitivity of the circuit to temperature is modeled by S = BR/(R + Rt)^2. If B = 3.7 and \"t\" is 90K (Kelvin), find the values of R and Rt that will make G = .4 and S = .001.\r
\n" ); document.write( "\n" ); document.write( "Answer: R= 187 , Rt = 645
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Algebra.Com's Answer #184337 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the 2 formulas you have to work with are:\r
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\n" ); document.write( "\n" ); document.write( "\"G+=+%28%28B%2At%29+%2F+%28R+%2B+R%5Bt%5D%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "and:\r
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\n" ); document.write( "\n" ); document.write( "\"S+=+%28B%2AR+%2F+%28%28R+%2B+R%5Bt%5D%29%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "R is the nominal value of a resistor.
\n" ); document.write( "R[t] is the value of the resistor at a certain temperature.
\n" ); document.write( "B is a constant.
\n" ); document.write( "t is the temperature using the Kelvin Scale.
\n" ); document.write( "S is the sensitivity of the circuit to temperature.\r
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\n" ); document.write( "\n" ); document.write( "Your problem is:\r
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\n" ); document.write( "\n" ); document.write( "\"If B = 3.7 and \"t\" is 90K (Kelvin), find the values of R and Rt that will make G = .4 and S = .001. (Answer: R= 187 , Rt = 645)\"\r
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\n" ); document.write( "\n" ); document.write( "We have:\r
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\n" ); document.write( "\n" ); document.write( "B = 3.7
\n" ); document.write( "t = 90
\n" ); document.write( "G = .4
\n" ); document.write( "S = .001\r
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\n" ); document.write( "\n" ); document.write( "We want to find R and R[t].\r
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\n" ); document.write( "\n" ); document.write( "The first formula is:\r
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\n" ); document.write( "\n" ); document.write( "\"G+=+%28%28B%2At%29+%2F+%28R+%2B+R%5Bt%5D%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Substituting in this formula gets:\r
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\n" ); document.write( "\n" ); document.write( "\".4+=+%28%283.7%2A90%29+%2F+%28R+%2B+R%5Bt%5D%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "We divide both sides of this equation by .4 and we multiply both sides of this equation by (R + R[t]) to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%28R+%2B+R%5Bt%5D%29+=+%28%283.7%2A90%29+%2F+.4%29\"\r
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\n" ); document.write( "\n" ); document.write( "We solve for (R + R[t] to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%28R+%2B+R%5Bt%5D%29+=+832.5\"\r
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\n" ); document.write( "\n" ); document.write( "The second formula is:\r
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\n" ); document.write( "\n" ); document.write( "\"S+=+%28%28B%2AR%29+%2F+%28%28R+%2B+R%5Bt%5D%29%5E2%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "We substitute in this formula to get:\r
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\n" ); document.write( "\n" ); document.write( "\".001+=+%28%283.7%2AR%29+%2F+%28832.5%5E2%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "S and B were given.
\n" ); document.write( "R + R[t] was calculated from the first equation.\r
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\n" ); document.write( "\n" ); document.write( "We multiply both sides of this equation by (832.5)^2 and we divide both sides of this equation by 3.7 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"R+=+%28.001+%2A+%28832.5%29%5E2%29%2F3.7%29\"\r
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\n" ); document.write( "\n" ); document.write( "We solve for R to get R = 187.325\r
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\n" ); document.write( "\n" ); document.write( "Since R + R[t] = 832.5, this means that R[t] = 832.5 - 187.325 = 645.1875\r
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\n" ); document.write( "\n" ); document.write( "we round these out to get:\r
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\n" ); document.write( "\n" ); document.write( "R = 187
\n" ); document.write( "R[t] = 645\r
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\n" ); document.write( "\n" ); document.write( "This agrees with the answers you provided.\r
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\n" ); document.write( "\n" ); document.write( "The key was solving for R + R[t] together in the first equation and then using that value to solve for R in the second equation.\r
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\n" ); document.write( "\n" ); document.write( "Once we knew R, getting R[t] was a simple matter of subtraction.\r
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\n" ); document.write( "\n" ); document.write( "I think that's what you were looking for.\r
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\n" ); document.write( "\n" ); document.write( "Let me know if otherwise.\r
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