document.write( "Question 252412: I have been sitting here for hours trying to figure the following problems. I am working on Non-Linear Systems and have to solve the following systems. No matter how I work it I can't seem to come to a solution.\r
\n" ); document.write( "\n" ); document.write( "1) {7x-8y=24
\n" ); document.write( " {xy^2=1\r
\n" ); document.write( "\n" ); document.write( "2) {(x+1)^2 - (y-1)^2 = 20
\n" ); document.write( " {x^2 - (y+2)^2 - 24\r
\n" ); document.write( "\n" ); document.write( "Thank you - Lori
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Algebra.Com's Answer #184310 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Even though these are non-linear equations, we can still use substitution to solve them. I'll do the first one to get you started. If that doesn't help either repost or ask me.\r
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\n" ); document.write( "\n" ); document.write( "\"xy%5E2=1\" Start with the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x=1%2F%28y%5E2%29\" Divide both sides by {{y^2}}} to isolate 'x'.\r
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\n" ); document.write( "\n" ); document.write( "\"7x-8y=24\" Move onto the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"7%281%2F%28y%5E2%29%29-8y=24\" Plug in \"x=1%2F%28y%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"7-8y%5E3=24y%5E2\" Multiply EVERY term by the LCD \"y%5E2\" to clear out the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"-8y%5E3-24y%5E2%2B7=0\" Get every term to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"8y%5E3%2B24y%5E2-7=0\" Multiply every term by -1.\r
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\n" ); document.write( "\n" ); document.write( "Now use the rational root theorem to find that \"y=1%2F2\" is a root to the polynomial equation above. In other words, if you plug in \"y=1%2F2\" into \"8y%5E3%2B24y%5E2-7\", you will get 0. Because of this fact, this means that \"2y-1\" is a factor of \"8y%5E3%2B24y%5E2-7\"\r
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\n" ); document.write( "\n" ); document.write( "Now use polynomial long division to find that \"%288y%5E3%2B24y%5E2-7%29%2F%282y-1%29=4y%5E2%2B14y%2B7\". So \"8y%5E3%2B24y%5E2-7=%282y-1%29%284y%5E2%2B14y%2B7%29\"\r
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\n" ); document.write( "\n" ); document.write( "This tells us that \"%282y-1%29%284y%5E2%2B14y%2B7%29=0\". Since we know that \"2y-1=0\" gives a root of \"1%2F2\", we can ignore this equation. So the next step is to solve \"4y%5E2%2B14y%2B7=0\" for 'y'. Use the quadratic equation to find the next two solutions of \"y=%28-7%2Bsqrt%2821%29%29%2F4\" or \"y=%28-7-sqrt%2821%29%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "So the three solutions in terms of 'y' are \"y=1%2F2\", \"y=%28-7%2Bsqrt%2821%29%29%2F4\" or \"y=%28-7-sqrt%2821%29%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "From here, plug each solution (in terms of 'y') into \"x=1%2F%28y%5E2%29\" to find the corresponding solution in terms of 'x'.\r
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\n" ); document.write( "\n" ); document.write( "I skipped a bit of steps (since they're a bit long and I'm out of time for now), so feel free to ask about any step.
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