document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31870>Question 31870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i had to solve the equation for y. the equation was (sqrt of 2y) +3=11, my answer was 4 ? please help.i hope i typed the equation right the 2y are under the radical sign. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18431 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sqrt(2y) + 3 = 11<BR>\n" );
document.write( "sqrt(2y)=8<BR>\n" );
document.write( "Square both sides to get:<BR>\n" );
document.write( "2y=64<BR>\n" );
document.write( "y=32<BR>\n" );
document.write( "Check the answer:<BR>\n" );
document.write( "sqrt(2(32))+3=11<BR>\n" );
document.write( "sqrt(64)+3+11<BR>\n" );
document.write( "8+3=11<BR>\n" );
document.write( "11=11<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );