document.write( "Question 252350: For certain arithmetic sequence, S 21= 546, S 22= 660 and d=8; determine S 23. \n" ); document.write( "
Algebra.Com's Answer #184273 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! First, we start with three formulas:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This gives us the nth term of the arithmetic sequence.\r \n" ); document.write( "\n" ); document.write( "SUM(n=1 to K) (constant) = K*constant\r \n" ); document.write( "\n" ); document.write( "SUM(n=1 to k)(n) = k(k+1)/2.\r \n" ); document.write( "\n" ); document.write( "We want SUM(n=1 to k) {A1 + 8n - 8}\r \n" ); document.write( "\n" ); document.write( "this can be expressed as\r \n" ); document.write( "\n" ); document.write( "SUM(n=1 to k) {A1} + SUM(n=1 to k) {8n} - SUM(n=1 to k) {8}\r \n" ); document.write( "\n" ); document.write( "This gives us kA1 + 8(k)(K+1)/2 - 8k\r \n" ); document.write( "\n" ); document.write( "Now \n" ); document.write( "S21 = 21A1 + 4(21)(22) - 8(21) = 546 \n" ); document.write( "S22 = 22A1 + 4(22)(23) - 8(22) = 660\r \n" ); document.write( "\n" ); document.write( "Subtracting the first from the second, we get\r \n" ); document.write( "\n" ); document.write( "A1 + 176 - 8 = 114\r \n" ); document.write( "\n" ); document.write( "A1 = -54.\r \n" ); document.write( "\n" ); document.write( "Now, we have the formula for Tn as\r \n" ); document.write( "\n" ); document.write( "Tn = -54 + 8(n-1)\r \n" ); document.write( "\n" ); document.write( "The sum of the first 23 terms can be expressed as\r \n" ); document.write( "\n" ); document.write( "SUM(n=1 to 23) {-54 + 8n - 8}\r \n" ); document.write( "\n" ); document.write( "SUM(n=1 to 23) {-54} + SUM(n=1 to 23) {8n} - SUM(n=1 to 23) {8}\r \n" ); document.write( "\n" ); document.write( "-54*23 + 8(23)(24)/2 - 8(23)\r \n" ); document.write( "\n" ); document.write( "-1242 + 2208 -184 = 782.\r \n" ); document.write( "\n" ); document.write( "S23 = 782. \n" ); document.write( " |