document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252386>Question 252386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) if the product (2x+3)(x+k)is 2x to the 2nd power + 13x+15 find the value of k\r<BR>\n" );
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document.write( "2)write a quadratic expression that is the difference of two squares.\r<BR>\n" );
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document.write( "3)factor 15m to the 4 power - 6m to the 2nd power + 9m\r<BR>\n" );
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document.write( "4)14x to the 5th power - 49x to the 8th power\r<BR>\n" );
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document.write( "5) subtract (-8x to the 4th power +3x)-(5x-4-x to the 4th power) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184264 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184264\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3*k=15<BR>\n" );
document.write( "k=5<BR>\n" );
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document.write( "Ed </SPAN>\n" );
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