document.write( "Question 252388: 1) if the product (2x+3)(x+k)is 2x to the 2nd power + 13x+15 find the value of k
\n" ); document.write( "2)write a quadratic expression that is the difference of two squares.
\n" ); document.write( "3)factor 15m to the 4 power - 6m to the 2nd power + 9m
\n" ); document.write( "4)14x to the 5th power - 49x to the 8th power
\n" ); document.write( "5) subtract (-8x to the 4th power +3x)-(5x-4-x to the 4th power)
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Algebra.Com's Answer #184252 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
you have too many questions lumped together.
\n" ); document.write( "I'll answer one of them
\n" ); document.write( "(2x+3)(x+k)=2x^2+13x+15
\n" ); document.write( "k=?
\n" ); document.write( "let's multiply out the two factors using foil
\n" ); document.write( "2x^2 so far so good
\n" ); document.write( "now inner and outer
\n" ); document.write( "2xk+3x
\n" ); document.write( "last
\n" ); document.write( "3k
\n" ); document.write( "my first guess is that k=5
\n" ); document.write( "since 3*5=15 and we have 3k as the final term
\n" ); document.write( "subtract3xfrom 13x we get 10 x
\n" ); document.write( "so 2xk is 10x
\n" ); document.write( "so k is indeed 5
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