document.write( "Question 252389: i dont have a problem its more of a question with expression i know you have to do the same opperation to each side but how do you figure out wich number to use, allong with what action * - + or/? \n" ); document.write( "
Algebra.Com's Answer #184248 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
somwhow you missed the intro to algebra or it wasn't presented.
\n" ); document.write( "generally when we are performing operations on both sides we have a picture of what we want at the end.
\n" ); document.write( "What do we want at the end is all the numbers on one side and the letters on the other.
\n" ); document.write( "why ?because we want to solve for the letter in terms of the numbers
\n" ); document.write( "for example
\n" ); document.write( "52x-2=6+50x
\n" ); document.write( "if we subtract 50x from both sides we will have x only on one side
\n" ); document.write( "2x-2=6
\n" ); document.write( "now we have all the letters on one side but we have numb ers on both sides
\n" ); document.write( "add two why 2 because 2-2=0
\n" ); document.write( "which will get rid of one more number on the left.
\n" ); document.write( "2x=6+2
\n" ); document.write( "2x=8
\n" ); document.write( "we are almost there
\n" ); document.write( "we still have that 2 on the left
\n" ); document.write( "so how can we get rid of it
\n" ); document.write( "divide by 2
\n" ); document.write( "because 2/2=1
\n" ); document.write( "so now we have 8/2 qnd 2/2
\n" ); document.write( "x=4\r
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