document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252297>Question 252297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the domain of the variable x in the equation y = (3x + 5)/(2x^2 + 5x - 3)? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184164 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find domain, all you need to do is ask two questions: <BR>\n" );
document.write( "Question #1 \"is the variable in a square root?\" If no, move to question 2. If yes set the junk under the root >=0.<BR>\n" );
document.write( "Question #2 \"is the variable in the denominator?\" If no, then you have answered no to both questions and you say \"all reals\". If yes, however, remember that the denominator can never = 0. So, we set denominator junk not = 0. This is what the question has.\r<BR>\n" );
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document.write( "step 1: factor -> 2X^2 + 5X - 3 not = 0. (2x-1)(x+3) not = 0.\r<BR>\n" );
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document.write( "step 2: solve each part for X. <BR>\n" );
document.write( "2X-1 not = 0. X not equal 1/2.<BR>\n" );
document.write( "X+3 not equal 0. X not equal -3.\r<BR>\n" );
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document.write( "we have our domains: all real except -2 and 1/2. </SPAN>\n" );
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