document.write( "Question 252314: mary has $3.75 in nickels, dimes, and quarters. She has three more quarters than dimes. She has twice as many nickels as quarters. How many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #184151 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! This requires a few equations. First Let N = nickel, D = dime, and Q = quarter. From the first sentence, we get \n" ); document.write( " \n" ); document.write( "This equation is the \"value\" equation. Notice also I don't use decimal points. Easier to get rid of them I think. Next, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Put all of this together using only Q, we get \n" ); document.write( "5(2Q) + 10(Q-3) + 25Q = 375 \n" ); document.write( "Solving for Q, you get Q = 9. \n" ); document.write( "Find the others, N = 18 and D = 6. So we have 18 nickels, 6 dimes, and 9 quarters. \n" ); document.write( " |