document.write( "Question 252309: The equation 2x^4 − 3x^3 − 14 x^2 − 22x − 8 = 0 has two real and two complex
\n" ); document.write( "solutions. What is the product of the two complex solutions? \n" ); document.write( "

Algebra.Com's Answer #184149 by drk(1908) $\"\"$ $\"About$

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Let's look at this using Descartes rule of signs. X = 4 and X = -2 will generate roots.
\n" ); document.write( "X = 4 divides the original polynomial with an answer of: $\"2X%5E3+%2B+5X%5E2+%2B+6X+%2B+2\"$
\n" ); document.write( "X = -1/2 divides the second polynomial with an answer of: $\"2X%5E2+%2B+4X+%2B+4+\"$
\n" ); document.write( "Set this polynomial = 0 and use quadratic. We get X = $\"-1+%2B-+isqrt%282%29\"$ \n" ); document.write( "

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