document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252316>Question 252316</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i solve for x and y      -3x+4y=-7     -8x-3y=23 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184148 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve either equation for x or y in terms of the other and then substitute that result in the other equation such that you will have either all x's or y's in that equation\r<BR>\n" );
document.write( "\n" );
document.write( "-3x+4y=-7<BR>\n" );
document.write( "add 3x to both sides<BR>\n" );
document.write( "4y=3x-7<BR>\n" );
document.write( "divide both sides by 4<BR>\n" );
document.write( "y=3x/4-7/4<BR>\n" );
document.write( "substitute 3x/4-7/4 for y in the other equation and solve for x<BR>\n" );
document.write( "then put that number in either of the original equation and solve for <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );