document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252288>Question 252288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the diagonal of a rectangle has length 7 feet and the rectangle’s area is 16 square feet, what is the perimeter of the rectangle in feet?\r<BR>\n" );
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document.write( "a 10 feet b  15 feet  c 18 feet d  23 feet   e 26 feet  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184137 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184137\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FOR THE AREA OF THE RECTANGLE:<BR>\n" );
document.write( "XY=16 OR X=16/Y<BR>\n" );
document.write( "FOR THE TRIANGLE:<BR>\n" );
document.write( "X^2+Y^2=7^2<BR>\n" );
document.write( "(16/Y)^2+Y^2=49<BR>\n" );
document.write( "(256/Y^2)+Y^2=49<BR>\n" );
document.write( "(256+Y^4)/Y^2=49<BR>\n" );
document.write( "256+Y^4=49Y^2<BR>\n" );
document.write( "Y^4-49Y^2+256=0<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Y%5E2+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"Y%5E2+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "Y^2=(49+-SQRT[-49^2-4*1*256])/2*1<BR>\n" );
document.write( "Y^2=(49+-SQRT[2,401-1.024])/2<BR>\n" );
document.write( "Y^2=(49+-SQRT1,377)/2<BR>\n" );
document.write( "Y^2=(49+-37.108)/2<BR>\n" );
document.write( "Y^2=(49+37.108)/2<BR>\n" );
document.write( "Y^2=86.108/2<BR>\n" );
document.write( "Y^2=43.05 <BR>\n" );
document.write( "Y=SQRT43.05<BR>\n" );
document.write( "Y=6.56 ANS. THEN X=2.44<BR>\n" );
document.write( "Y^2=(49-37.108)/2<BR>\n" );
document.write( "Y^2=11.892/2<BR>\n" );
document.write( "Y^2=5.95 <BR>\n" );
document.write( "Y=SQRT5.95<BR>\n" );
document.write( "Y=2.44 ANS. THEN X=6.56<BR>\n" );
document.write( "PROOFS:<BR>\n" );
document.write( "6.56*2.44=16<BR>\n" );
document.write( "16~16<BR>\n" );
document.write( "6.56^2+2.44^2=49<BR>\n" );
document.write( "43.03+5.954=49<BR>\n" );
document.write( "49~49<BR>\n" );
document.write( "tHUS THE PERIMETERIS:<BR>\n" );
document.write( "2*6.56+2*2.44=13.12+4.88=18 FT. IS THE PERIMETER. <BR>\n" );
document.write( "ANSWER C) </SPAN>\n" );
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