document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31854>Question 31854</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the orgianl amount when;\r<BR>\n" );
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document.write( "carbon 14    half life is <BR>\n" );
document.write( "5730   after 1000 year is 2g. what is the original amount. the answer is 2.26g. i need to know the formula. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18412 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Amount now = (Original amount)*(1/2)^(t/5730)<BR>\n" );
document.write( "2 = P (1/2)^(1000/5730)<BR>\n" );
document.write( "2= P (.8861)<BR>\n" );
document.write( "P=2.2572...<BR>\n" );
document.write( "Original amount was 2.2572.. grams<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
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