document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252278>Question 252278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> hi! how do u make a algebraic equation on this question: If the sides of a square are increased by 5cm, the area of the new square is four times the area of the original square. Find the length of a side of the original square. <BR>\n" );
document.write( "Can you please show me how to solve this using the check. thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #184117 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=184117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> equation is (x+5)^2 = 4x^2\r<BR>\n" );
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document.write( "(x+5)^2 = 4x^2<BR>\n" );
document.write( "x^2+10x+25 = 4x^2<BR>\n" );
document.write( "-3x^2+10x+25 = 0<BR>\n" );
document.write( "(x-5)(3x+5) = 0<BR>\n" );
document.write( "x-5=0    or    3x+5=0<BR>\n" );
document.write( "x=5      or    x=-5/3\r<BR>\n" );
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document.write( "Only answer is x=5. Original side length is 5 cm\r<BR>\n" );
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document.write( "Check: \r<BR>\n" );
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document.write( "Original area = 5*5 = 25<BR>\n" );
document.write( "New area = (5+5)*(5+5) = 10*10 = 100 = 4*25 </SPAN>\n" );
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