document.write( "Question 252265: Hello \r
\n" ); document.write( "\n" ); document.write( "I have a problem that is nonlinear and cramer's rule or Gaussian elimination can't be used for. I'm trying to use substitution and factoring for this one but I'm coming up with the right thing... And I know its something that I'm missing I just can't see it.... it seems like the simplier the problem, I make mistakes.
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\n" ); document.write( "Could you please assist me with solving this problem ..
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\n" ); document.write( "\n" ); document.write( "y=x^2-4x+7
\n" ); document.write( "y=x+1\r
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Algebra.Com's Answer #184085 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"y=x%5E2-4x%2B7\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B1=x%5E2-4x%2B7\" Plug in \"y=x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2-4x%2B7-x-1\" Get everything to one side.\r
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\n" ); document.write( "\n" ); document.write( "\"0=x%5E2-5x%2B6\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"0=%28x-3%29%28x-2%29\" Factor the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x-3=0\" or \"x-2=0\" Use the zero product property.\r
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\n" ); document.write( "\n" ); document.write( "\"x=3\" or \"x=2\" Solve for 'x' in each equation.\r
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\n" ); document.write( "\n" ); document.write( "Now for each 'x', plug them into \"y=x%2B1\" to find the corresponding 'y' values.\r
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\n" ); document.write( "\n" ); document.write( "So when \"x=3\", then \"y=3%2B1=4\" which gives the first ordered pair (3,4)\r
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\n" ); document.write( "\n" ); document.write( "and when \"x=2\", then \"y=2%2B1=3\" which gives the second ordered pair (2,3)\r
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