document.write( "Question 252232: Suppose that the electricity bill is determined only by multiplying the number of kilowatt hours used by the cost per kilowatt hour. Last February Ben’s electric bill was $50. This February the number of kilowatt hours used was 20% higher and the rate per kilowatt hour was 8% lower. To the nearest percent, select the percentage by which his electric bill has changed.\r
\n" ); document.write( "\n" ); document.write( "A. 12% increase B. 10% increase C. 0% D. 10% decrease E. 12% decrease
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Algebra.Com's Answer #184064 by Theo(13342)\"\" \"About 
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c = cost per kilowatt hour
\n" ); document.write( "k = number of kilowatt hours.\r
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\n" ); document.write( "\n" ); document.write( "you get:\r
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\n" ); document.write( "\n" ); document.write( "c*k = 50\r
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\n" ); document.write( "\n" ); document.write( "that was last february.\r
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\n" ); document.write( "\n" ); document.write( "this february the bill is:\r
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\n" ); document.write( "\n" ); document.write( ".92*c*1.2*k = ?????\r
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\n" ); document.write( "\n" ); document.write( "this is the same as:\r
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\n" ); document.write( "\n" ); document.write( ".92*1.2*c*k = ?????\r
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\n" ); document.write( "\n" ); document.write( "we know that c*k is equal to $50.00, so the equation becomes:\r
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\n" ); document.write( "\n" ); document.write( ".92*1.2*50 = ?????\r
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\n" ); document.write( "\n" ); document.write( "this becomes:\r
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\n" ); document.write( "\n" ); document.write( ".92*1.2*50 = 55.2\r
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\n" ); document.write( "\n" ); document.write( "this years bill should be $55.20\r
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\n" ); document.write( "\n" ); document.write( "55.2/50 = 1.104 - 1 = .104 * 100% = 10.4%.\r
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\n" ); document.write( "\n" ); document.write( "rounded to the nearest integer, this because a 10% increase which would be selection B.\r
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\n" ); document.write( "\n" ); document.write( "example:\r
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\n" ); document.write( "\n" ); document.write( "assume the cost per kilowatt hour was 20 cents / 100 = $.20\r
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\n" ); document.write( "\n" ); document.write( "if the bill was 50, then the kilowatt hours were 250.\r
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\n" ); document.write( "\n" ); document.write( "drop the cost by 8% to get c = .2 * (1-.08) = .2 * .92 = .184 per kilowatt hour.\r
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\n" ); document.write( "\n" ); document.write( "raise the number of kilowatt hours by 20% to get 250 * (1 + .2) = 250 * 1.2 = 300 kilowatt hours.\r
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\n" ); document.write( "\n" ); document.write( "figures for last february were:\r
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\n" ); document.write( "\n" ); document.write( "c = .2
\n" ); document.write( "k = 250\r
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\n" ); document.write( "\n" ); document.write( "figures for this february are:\r
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\n" ); document.write( "\n" ); document.write( "c = .184
\n" ); document.write( "k = 300\r
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\n" ); document.write( "\n" ); document.write( ".184 * 300 = 55.2\r
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\n" ); document.write( "\n" ); document.write( "cost for last february was $50.00
\n" ); document.write( "cost for this february is $55.20\r
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\n" ); document.write( "\n" ); document.write( "55.2 / 50 = 1.104 - 1 = .104 * 100% = 10.4% rounded to the nearest integer = 10%.\r
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