document.write( "Question 252246: Susan left her home, on foot, at 9:00 am at 1.5 mph. At 10:00 am her friend,
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document.write( "following the same route, ran at 5.25 mph to meet her. How many minutes, after
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document.write( "10:00 am, did the two friends meet? \n" );
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Algebra.Com's Answer #184061 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Susan left her home, on foot, at 9:00 am at 1.5 mph. At 10:00 am her friend, \n" ); document.write( "following the same route, ran at 5.25 mph to meet her. How many minutes, after \n" ); document.write( "10:00 am, did the two friends meet? \n" ); document.write( ". \n" ); document.write( "Apply the distance formula: \n" ); document.write( "d = rt \n" ); document.write( "d is distance \n" ); document.write( "r is rate or speed \n" ); document.write( "t is time \n" ); document.write( ". \n" ); document.write( "Let x = minutes after 10 am when the two friends meet \n" ); document.write( "then \n" ); document.write( "1.5(x/60 + 1) = 5.25(x/60) \n" ); document.write( "Multiplying both sides by 60: \n" ); document.write( "1.5(x + 60) = 5.25x \n" ); document.write( "1.5x + 90 = 5.25x \n" ); document.write( "90 = 3.75x \n" ); document.write( "24 minutes = x \n" ); document.write( " \n" ); document.write( " |