document.write( "Question 252246: Susan left her home, on foot, at 9:00 am at 1.5 mph. At 10:00 am her friend,
\n" ); document.write( "following the same route, ran at 5.25 mph to meet her. How many minutes, after
\n" ); document.write( "10:00 am, did the two friends meet?
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Algebra.Com's Answer #184061 by nerdybill(7384)\"\" \"About 
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Susan left her home, on foot, at 9:00 am at 1.5 mph. At 10:00 am her friend,
\n" ); document.write( "following the same route, ran at 5.25 mph to meet her. How many minutes, after
\n" ); document.write( "10:00 am, did the two friends meet?
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\n" ); document.write( "Apply the distance formula:
\n" ); document.write( "d = rt
\n" ); document.write( "d is distance
\n" ); document.write( "r is rate or speed
\n" ); document.write( "t is time
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\n" ); document.write( "Let x = minutes after 10 am when the two friends meet
\n" ); document.write( "then
\n" ); document.write( "1.5(x/60 + 1) = 5.25(x/60)
\n" ); document.write( "Multiplying both sides by 60:
\n" ); document.write( "1.5(x + 60) = 5.25x
\n" ); document.write( "1.5x + 90 = 5.25x
\n" ); document.write( "90 = 3.75x
\n" ); document.write( "24 minutes = x
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