document.write( "Question 252244: If x and y are natural numbers, then how many solutions does the equation
\n" ); document.write( "x + y = 12 have? \n" ); document.write( "

Algebra.Com's Answer #184052 by Theo(13342) $\"\"$ $\"About$

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it depends on whether you include 0 as part of the natural number set.\r
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\n" ); document.write( "\n" ); document.write( "natural number can be either positive integers or non-negative integers.\r
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\n" ); document.write( "\n" ); document.write( "your equation is x + y = 12.\r
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\n" ); document.write( "\n" ); document.write( "assuming non-negative integers, then the possible solutions are:\r
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\n" ); document.write( "\n" ); document.write( "0 + 12
\n" ); document.write( "1 + 11
\n" ); document.write( "2 + 10
\n" ); document.write( "3 + 9
\n" ); document.write( "4 + 8
\n" ); document.write( "5 + 7
\n" ); document.write( "6 + 6\r
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\n" ); document.write( "\n" ); document.write( "assuming positive integers only, then the possible solutions are the same except that you would remove the 0 as one of the possible solutions.\r
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\n" ); document.write( "\n" ); document.write( "positive integers DISABLED_event_only= 6 possible ways to add x + y = 12\r
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\n" ); document.write( "\n" ); document.write( "non-negative integers DISABLED_event_only= 7 possible ways to add x + y = 12\r
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