document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251190>Question 251190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You have 240 feet of wooden fencing to form two adjacent rectangular corrals as shown you want each corral to have an area of 1000 square feeet. A. Show that w+ 80- 4/3l. B. Use your answer from part a to find the possible dimensions of each corral.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183992 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have a figure to look at which is good. There are 4 Length parts and 3 Width parts . . . Hope that makes sense. The perimeter can be expressed as 4L + 3W = 240. Now we have 2 pens each with an area of LW = 1000.<BR>\n" );
document.write( "PART A of your question want you to solve for W. <BR>\n" );
document.write( "4L + 3W = 240<BR>\n" );
document.write( "3W = 240 - 4L<BR>\n" );
document.write( "W = 80 - (4/3)L<BR>\n" );
document.write( "PART B:<BR>\n" );
document.write( "step 1 - solve LW = 1000 for L. We get L = 1000/W.<BR>\n" );
document.write( "step 2 - substitute L = 1000/W into the perimeter equation. We get 4000/W + 3W = 240.<BR>\n" );
document.write( "step 3 - multiply both sides by W. We get 4000 + W^2 = 240W.<BR>\n" );
document.write( "step 4 - solve for W using the quadratic. We get W = 18.0196.<BR>\n" );
document.write( "step 5 - solve for L. L = 1000/W = 55.495<BR>\n" );
document.write( "The dimensions of each corral is ~ 18 x 55.5. </SPAN>\n" );
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