document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252174>Question 252174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1\3(c+1)=1\6(3c-5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183951 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In this question, it appears as through we are to solve for C in the equation:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28C%2B1%29%2F3+=+%283C-5%29%2F6 ALIGN=MIDDLE  ALT=\"%28C%2B1%29%2F3+=+%283C-5%29%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "\n" );
document.write( "The standard way to solve is cross multiplication. Make sure you distribute all the way through.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6C+%2B+6+=+9C+-+15 ALIGN=MIDDLE  ALT=\"6C+%2B+6+=+9C+-+15\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "Now, we solve for C using standard rules:\r<BR>\n" );
document.write( "\n" );
document.write( "21 = 3C -> C = 7. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );