document.write( "Question 31795: Question: Find the equation of the ellipise whose centers is (-4,-5), has a vertex at (2,-5) and a minor axis of length 6. \r
\n" );
document.write( "\n" );
document.write( "(A) (x+4)^2/9 + (y+5)^2/36 = 1
\n" );
document.write( "(B) (x+4)^2/36 + (y+5)^2/9 =1
\n" );
document.write( "(C) none of these
\n" );
document.write( "(D) x^2/36 + y^2/9 =1 \r
\n" );
document.write( "\n" );
document.write( "Thank you!
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #18395 by mukhopadhyay(490)![]() ![]() ![]() You can put this solution on YOUR website! Standard equation of ellipse is: \n" ); document.write( "(x-h)^2/a^2 + (y-k)^2/b^2 = 1 where (h,k) is the center, a=1/2(length of one axis), and b=1/2(length of another axis); \n" ); document.write( "We know that (h,k) = (-4,-5) \n" ); document.write( "So, the equation boils down to \n" ); document.write( "(x+4)^2/a^2 + (y+5)^2/b^2 = 1; \n" ); document.write( "Vertex is at (2,-5) and center is at (-4,-5). This says that the major axis is parallel to x-axis (because y-value for both of them is the same) and 1/2 of the length of the major axis 6 [6 comes from 2-(-4); difference of x-value between vertex and the center] \n" ); document.write( "So, a=6 and b=3 (6/2=3) \n" ); document.write( "Thus, the equation of the ellipse is \n" ); document.write( "(x+4)^2/6^2 + (y+5)^2/3^2 = 1 \n" ); document.write( "=>(x+4)^2/36 + (y+5)^2/9 = 1 \n" ); document.write( "Correct answer is B. \n" ); document.write( " \n" ); document.write( " |