document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252149>Question 252149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write a system of equations for the following:\r<BR>\n" );
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document.write( "A rectangle is 3times longer than it's width. The permiter is 44 cm.\r<BR>\n" );
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document.write( "A farmer grows only pumpkins & corn on a 420 acre farm. He wants to plant 250 more acres of corn than of umpkins. How many acres of each crop does he need to plant.\r<BR>\n" );
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document.write( "I figured the answers but do not know how to write a system of equations for them<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183930 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok, the easiest way to do this is to write down what you have:<BR>\n" );
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document.write( "(1)<BR>\n" );
document.write( "L = length   W=width<BR>\n" );
document.write( "if a rectangle is 3 times longer than wide you know:\r<BR>\n" );
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document.write( "L = 3W\r<BR>\n" );
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document.write( "and if the perimeter of a rectangle is all the sides added up you can say.\r<BR>\n" );
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document.write( "L+L+W+W=perimeter or 2L + 2W = perimeter.\r<BR>\n" );
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document.write( "so your two equation for the first system are:\r<BR>\n" );
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document.write( "L = 3W<BR>\n" );
document.write( "2L + 2W = 44  use substitution\r<BR>\n" );
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document.write( "2(3W) + 2W = 44<BR>\n" );
document.write( "6W + 2W = 44<BR>\n" );
document.write( "8W = 44<BR>\n" );
document.write( "w = 5.5cm   so sub back into orginal equation L=3W<BR>\n" );
document.write( "L= 3(5.5) = 16.5 cm\r<BR>\n" );
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document.write( "(2)<BR>\n" );
document.write( "p=pumpkin  c=corn\r<BR>\n" );
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document.write( "we know that together he wants 420 acres of both so:\r<BR>\n" );
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document.write( "p+c=420\r<BR>\n" );
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document.write( "and he wants 250 more acres of corn than pumpkin so\r<BR>\n" );
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document.write( "p=c+250\r<BR>\n" );
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document.write( "So your two equations are:<BR>\n" );
document.write( "p+c=420<BR>\n" );
document.write( "c=250+p\r<BR>\n" );
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document.write( "Use substitution again<BR>\n" );
document.write( "p + p + 250 = 420 Subtract 250 from both sides<BR>\n" );
document.write( "2p = 170  divide both sides by 2<BR>\n" );
document.write( "p=85acres\r<BR>\n" );
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document.write( "Sub back into orginal equation <BR>\n" );
document.write( "c=250+85<BR>\n" );
document.write( "c= 335acres\r<BR>\n" );
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document.write( "hope this helps\r<BR>\n" );
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