document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31790>Question 31790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist dilutes a 32% saline (salt) solution with water (0% saline) in order to produce 150 liters of 20% saline solution. How much water and how much 32% solution does she need to use?\r<BR>\n" );
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document.write( "Thank you for taking the time to answer my question.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18391 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18391\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount of salt used<BR>\n" );
document.write( "Let y be the amount of water used<BR>\n" );
document.write( "y=150-x (subsitution)<BR>\n" );
document.write( "32x+0y=150(20)<BR>\n" );
document.write( "Subsitute:<BR>\n" );
document.write( "32x+0(150-x)=3000<BR>\n" );
document.write( "32x=3000<BR>\n" );
document.write( "x=93.75<BR>\n" );
document.write( "y=150-93.75<BR>\n" );
document.write( "y=56.25<BR>\n" );
document.write( "Hence, a chemist uses 93.75 L of salt and 56.25L of water.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
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