document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251260>Question 251260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The amount of a chemical that will dissolve in a solution increases exponentially as the (Celcius) temperature t is increased according to the model A(t)=10e^.0095t.  At what temperature will 15g dissolve?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183909 by </B><A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><B>blwinbbbles(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=blwinbbbles><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=blwinbbbles><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This problem is not quite defined enough so I have to give you 2 answers.\r<BR>\n" );
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document.write( "(1)<BR>\n" );
document.write( "if the exponential (t) = temp. then:\r<BR>\n" );
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document.write( "15 = A(t)  so:\r<BR>\n" );
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document.write( "15 = 10e^.0095(t)  divide both sides by 10<BR>\n" );
document.write( "1.5 = e^.0095(t)  e is the inverse natural log (ln) of 1 so take the natural <BR>\n" );
document.write( "                  of both sides... that is usually (ln) on your calculator<BR>\n" );
document.write( "ln (1.5) = ln (e^.0095(t)<BR>\n" );
document.write( ".40546 = .0095(t)   by taking the ln of e brings the exponential down..(I am sorry that I do not remember the exact proof)\r<BR>\n" );
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document.write( "now divide both sides by .0095\r<BR>\n" );
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document.write( "42.68 = t  so the temperature is 42.68 degrees Celcius\r<BR>\n" );
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document.write( "(2)<BR>\n" );
document.write( "if the exponential (t) = 15 then\r<BR>\n" );
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document.write( "A(t) = 10e^.0095(15)<BR>\n" );
document.write( "A(t) = 10e^0.1425<BR>\n" );
document.write( "A(t) = 10(1.15315)  use the e^x key on your calculator..on mine it is a second<BR>\n" );
document.write( "                    function<BR>\n" );
document.write( "A(t) = 11.5 degrees Celcius\r<BR>\n" );
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document.write( "I hope this helps </SPAN>\n" );
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