document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252133>Question 252133</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fernando’s motorboat can travel 30 mi/hr in still water. <BR>\n" );
document.write( "If the boat can travel 9 miles downstream in the same time it takes to travel 1 miles upstream, what is the rate of the river’s current? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183903 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (30+x)*t=9<BR>\n" );
document.write( "(30-x)*t=1<BR>\n" );
document.write( "t=1/54 time<BR>\n" );
document.write( "x=24 rate of current\r<BR>\n" );
document.write( "\n" );
document.write( "another way of solving<BR>\n" );
document.write( "t=9/(30+x)<BR>\n" );
document.write( "t=1/(30-x)<BR>\n" );
document.write( "9/(30+x)=1/(30-x)<BR>\n" );
document.write( "x=24= rate of current<BR>\n" );
document.write( "check<BR>\n" );
document.write( "9/(30+24)=1/(30-24)<BR>\n" );
document.write( "9/54=1/6<BR>\n" );
document.write( "1/6=1/6<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );