document.write( "Question 252127: Solve this system for (x, y) : 2^x.4^y = 16 and 4^3x-2.(1/2)^y = 128 \n" ); document.write( "
Algebra.Com's Answer #183897 by vksarvepalli(154)\"\" \"About 
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2^x.4^y = 16 \r
\n" ); document.write( "\n" ); document.write( "so 2^x.2^2y = 2^4
\n" ); document.write( "=> 2^(x+2y) = 2^4
\n" ); document.write( "=> x+2y=4 -------------- 1\r
\n" ); document.write( "\n" ); document.write( "4^3x-2.(1/2)^y = 128
\n" ); document.write( "=> 2^(6x-4).2^(-y) = 2^7
\n" ); document.write( "=> 6x-4-y = 7
\n" ); document.write( "=> 6x-y=11 -------------- 2\r
\n" ); document.write( "\n" ); document.write( "solving equations 1 and 2 (multiply eq. 2 by 2 and add eq.1 )\r
\n" ); document.write( "\n" ); document.write( "x=2
\n" ); document.write( "y=1
\n" ); document.write( "
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